Gujarat Board Statistics Class 11 GSEB Solutions Chapter 4 Measures of Dispersion Ex 4.1 Textbook Exercise Questions and Answers.

## Gujarat Board Textbook Solutions Class 11 Statistics Chapter 4 Measures of Dispersion Ex 4.1

Question 1.

The following data refer to the heights in cms. of 10 students of a class. Find range and coefficient of range of height of the students.

Answer:

Here, x_{H} = 185 cm; x_{L}=145cm

Range of height:

R = x_{H} – x_{L}

= 185 – 145

= 40 cm

Coefficient of range = \(\frac{x_{\mathrm{H}}-x_{\mathrm{L}}}{x_{\mathrm{H}}+x_{\mathrm{L}}}\)

= \(\frac{185-145}{185+145}\)

= \(\frac{40}{330}\)

= 0.12

Question 2.

A bus company has 77 buses for travelling in the city. The information of number of passengers in bus on a particular day at a particular time is given below. Find the range and coefficient of range of number of passengers.

Answer:

Here. X_{H} = Maximum passengers travelling in a bus = 37

X_{L} = Minimum passengers travelling in a bus = 2

Range of number of passengers:

R = x_{H} – x_{L}

= 37 – 2

= 35 Passengers

Coefficient of range = \(\frac{\mathrm{R}}{x_{\mathrm{H}}+x_{\mathrm{L}}}\)

= \(\frac{35}{37+2}\)

= \(\frac{35}{39}\)

= 0.90

Question 3.

Using the following frequency distribution of marks of students of a school, find range and relative range of the marks:

Answer:

Here, x_{H} = Upper limit of the last class 70 – 80 = 80 marks

x_{L} = Lower limit of the initial class 20 – 30 = 20 marks

Range of marks of students :

R = x_{H} – x_{L}

= 80 – 20 = 60 marks

Relative range of marks:

Relative range = \(\frac{\mathrm{R}}{x_{\mathrm{H}}+x_{\mathrm{L}}}\)

= \(\frac{60}{80+20}\)

= \(\frac{60}{100}\)

= 0.60

Question 4.

The frequency distribution of daily income , (in thousand of 80 shops of an area is as follows. Find the absolute and the relative measure of range of daily income from it.

Answer:

Here, x_{H} = Upper limit of the last class 30 – 34 = â‚¹ 34

x_{L} = Lower limit of the initial class 5-9 = â‚¹ 5

Absolute measure of range of age:

R = x_{H} – x_{L}

= 34 – 5 = â‚¹ 29 thousand

Relative measure of range of age:

Coefficient of range = \(\frac{x_{\mathrm{H}}-x_{\mathrm{L}}}{x_{\mathrm{H}}+x_{\mathrm{L}}}=\frac{\mathrm{R}}{x_{\mathrm{H}}+x_{\mathrm{L}}}\)

= \(\frac{29}{34+5}\)

= \(\frac{29}{39}\)

= 0.74