Gujarat BoardĀ GSEB Textbook Solutions Class 6 Maths Chapter 10 Mensuration Ex 10.3 Textbook Questions and Answers.

## Gujarat Board Textbook Solutions Class 6 Maths Chapter 10 Mensuration Ex 10.3

Question 1.

Find the areas of the rectangles whose sides are:

(a) 3 cm and 4 cm

(b) 12 m and 21 m

(c) 2 km and 3 km

(d) 2 m and 70 cm

Solution:

(a) āµ Length of the rectangle = 4 cm

Breadth of the rectangle = 3 cm

ā“ Area = length Ć breadth

= 4 cm Ć 3 cm = 12 sq. cm

(b) āµ Length of the rectangle = 21 m

Breadth of the rectangle = 12 m

ā“ Area = length Ć breadth

= 21 m Ć 12 m = 252 sq. m

(c) āµ Length of the rectangle = 3 km

Breadth of the rectangle = 2 km

Area = length Ć breadth

= 3 km Ć 2 km = 6 sq. km

(d) āµ Length of the rectangle = 2 m = 200 cm

Breadth of the rectangle = 70 cm

Area = length Ć breadth

= 200 cm Ć 70 cm = 14000 sq. cm

Question 2.

Find the areas of the squares whose sides are:

(a) 10 cm

(b) 14 cm

(c) 5 m

Solution:

(a) āµ Side of the square = 10 cm

ā“ Area of the square = side Ć side

= 10 cm Ć 10 cm = 100 sq. cm

(b) āµ Side of the square = 14 cm

ā“ Area of the square = side Ć side

= 14 cm Ć 14 cm = 196 sq. cm

(c) āµ Side of the square = 5 m

Area of the square = side Ć side

= 5 m Ć 5 m = 25 sq. m

Question 3.

The length and breadth of the three rectangles are as given below:

(a) 9 m and 6 m

(b) 17 m and 3 m

(c) 4 m and 14 m

Which one has the largest area and which one has the smallest?

Solution:

(a) Area of rectangle = length Ć breadth

= 9 m Ć 6 m = 54 sq. m

(b) Area of rectangle = length Ć breadth

= 17 m Ć 3 m = 51 sq. m

(c) Area of rectangle = length Ć breadth

= 4 m Ć 14 m = 56 sq. m

Since, 56 > 54 > 51

ā“ The rectangle (c) has the largest area and the rectangle (b) has the smallest area.

Question 4.

The area of a rectangular garden 50 m long is 300 sq. m. Find the width of the garden.

Solution:

Area of the rectangular garden = 300 sq. m

Length of the rectangular garden= 50 m

ā“ The breadth of the garden =

Question 5.

What is the cost of tiling a rectangular plot of land 500 m long and 200 m wide at the rate of ā¹ 8 per hundred m sq?

Solution:

āµ Length of the rectangular plot = 500 m

The breadth of the rectangular plot = 200 m

ā“ Area of the plot = length Ć breadth

= 500 m Ć 200 m = 100000 sq. m

Cost of tiling for 100 sq. m area = ā¹ 8

Total cost of tiling the plot = \(\frac { 100000 }{ 100 }\) x 8

= ā¹ 1000 Ć 8 = ā¹ 8000

Question 6.

A table-top measures 2 m by 1 m 50 cm. What is its area in square metres?

Solution:

āµ 2 m by 1 m 50 cm means

Length = 2 m = 200 cm and

Breadth = 1 m 50 cm = 150 cm

ā“ Area = length Ć breadth

= 200 cm Ć 150 cm = 30000 sq. cm

ā“ The area of the table top = 30000 sq. cm

Note: For expressing square centimetres into square metres, we divide by 100 Ć 100.

Question 7.

A room is 4 m long and 3 m 50 cm wide. How many square metres of carpet is needed to cover the floor of the room?

Solution:

āµ Length of the room = 4 m = 400 cm

Breadth of the room = 3 m 50 cm = 350 cm

ā“ Area of the floor of the room = length Ć breadth = 400 cm Ć 350 cm

Thus, 14 sq. m of carpet is required to cover the floor of the room.

Question 8.

A floor is 5 m long and 4 m wide. A square carpet of sides 3 m is laid on the floor. Find the area of the floor that is not carpeted.

Solution:

Area of the floor = length x breadth

= 5 m Ć 4 m = 20 sq. m

Area of the square carpet = side x side

= 3 m Ć 3 m = 9 sq. m

ā“ Area of the floor uncovered = 20 sq. m – 9 sq m = 11 sq. m

Thus, 11 sq. m of the floor is not covered by the carpet.

Question 9.

Five square flower beds each of sides 1 m are dug on a piece of land 5 m long and 4 m wide. What is the area of the remaining part of the land?

Solution:

āµ Length of the piece of land = 5 m

The breadth of the piece of land = 4 m

ā“ Area of the piece of land = length Ć breadth

= 5 m Ć 4 m = 20 sq. m

Area of a āsquare flower bedā = side x side

= 1 m Ć 1 m = 1 sq. m

ā“ Area of 5 square flower beds

= 5 Ć 1 sq. m = 5 sq. m

ā“ Area of the remaining part

= 20 sq. m – 5 sq. m = 15 sq. m

Question 10.

By splitting the following figures into rectangles, find their areas. (The measures are given in centimetres.)

Solution:

(a) Let us split the given figure into various squares and rectangles as shown in the adjoining figure.

Now,

Area of rectangle I = length Ć breadth = 4 cm Ć 2 cm = 8 sq. cm

Area of square II = side Ć side = 3 cm Ć 3 cm = 9 sq. cm

Area of rectangle III = length Ć breadth = 2 cm Ć 1 cm = 2 sq. cm

Area of square IV = side Ć side = 3 cm Ć 3 cm = 9 sq. cm

ā“ Total area of the figure

= 8 sq. cm + 9 sq. cm + 2 sq. cm + 9 sq. cm = 28 sq. cm

(b) Splitting the given figure ill various rectangles, we have:

Area of rectangle I = length Ć breadth = 3 cm Ć 1 cm = 3 sq. cm

Area of rectangle II = length Ć breadth = 3 Ć 1 sq. cm = 3 sq. cm

Area of rectangle III = length Ć breadth = 3 Ć 1 sq. cm = 3 sq. cm

ā“ Total area of the figure

= Area of rectangle I + Area of rectangle II + Area of rectangle III

= 3 sq. cm + 3 sq. cm + 3 sq. cm = 9 sq. cm

Question 11.

Split the following shapes into rectangles and find their areas. (The measures are given in centimetres.)

Solution:

(a) Splitting the given figure into rectangles we have,

Area of rectangle I = length x breadth = 10 cm Ć 2 cm = 20 sq. cm

Area of rectangle II = length x breadth = 10 cm Ć 2 cm = 20 sq. cm

ā“ Total area of the figure

= 20 sq. cm + 20 sq. cm = 40 sq. cm

(b) Area of square I = 7 cm Ć 7 cm = 49 sq. cm

Area of rectangle II = (7 + 7 + 7) cm x 7 cm = 21 cm Ć 7 cm = 147 sq. cm

Area of square III = 7 cm Ć 7 cm = 49 sq. cm

ā“ Total area of the given figure

= Area of I + Area of II + Area of III

= 49 sq. cm + 147 sq. cm + 49 sq. cm = 245 sq. cm

(c) Area of rectangle I = 5 cm x 1 cm = 5 sq. cm

Area of rectangle II = 4 cm x 1 cm = 4 sq. cm

ā“ Total area of the given figure = Area of rectangle I + Area of rectangle II

= 5 sq. cm + 4 sq cm = 9 sq. cm

Question 12.

How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed o fit in a rectangular region whose length and breadth are respectively:

(a) 100 cm and 144 cm

(b) 70 cm and 36 cm

Solution:

Area of the rectangular tile = 12 cm Ć 5 cm = 60 sq cm

(a) Area of the rectangular region = length Ć breadth

= 100 cm Ć 144 cm = 14400 sq. cm

ā“ Number of tiles required to cover area of 14400 sq. cm

(b) āµ Area of the rectangular region = length Ć breadth

= 70 cm Ć 36 cm = 2520 sq. cm

Area of the tile = 60 sq. cm

ā“ Number of tiles required