Gujarat BoardĀ GSEB Textbook Solutions Class 6 Maths Chapter 6 Integers InText Questions and Answers.

## Gujarat Board Textbook Solutions Class 6 Maths Chapter 6 Integers InText Questions

Try These (NCERT Page 116)

Question 1.

Write the following numbers with appropriate signs:

(a) 100 m below sea level.

(b) 25Ā°C above 0Ā°C temperature.

(c) 15Ā°C below 0Ā°C temperature.

(d) Any five numbers less than 0.

Solution:

(a) 100 m below sea level ā – 100 m

(b) 25Ā° above 0Ā°C temperature ā + 25Ā° C

(c) 15Ā°C below 0Ā°C temperature ā – 15Ā° C

(d) Five numbers less than 0: { – 1, – 3, – 10, – 25, – 105 }

Note:

(i) If profit is represented by ā+ā sign, then loss may be represented by ā-ā sign.

(ii) If going up is represented by ā+ā sign, then going down may be represented by ā-ā sign.

(iii) If earnings are represented by ā+ā sign, then spending may be represented by ‘-‘ sign.

(iv) If temperature above 0Ā° is ā+ā sign, then temperature below 00 may be represented by ‘-‘ sign.

(v) If depositing money to bank is ā+ā sign, then withdrawal is ‘-‘ sign.

Try These (NCERT Page 118)

Question 1.

Mark 3, 7, – 4, – 8, – 1 and – 3 on the number line.

Solution:

Given numbers are marked on the number line as shown below:

Note: Look at the number line given here. We find that for every integer to the right of zero there is a corresponding integer to the left of zero (at the same distance from zero but with a negative sign). Similarly, for every integer to the left of zero. there is a corresponding integer to the right of zero (at the same distance from zero but with a positive sign).

Try These (Page 119)

Question 1.

Compare the following pairs of numbers using> or <.

Solution:

Try These (Page 125)

Question 1.

Draw a figure on the ground in the form of a horizontal number line as shown below. Frame questions as given in the said example and ask your friends.

Solution:

Do it yourself.

Try These (Page 125)

Question 1.

Find the answers of the following additions:

(a) ( -11) + ( -12)

(b) (+10) +(+4)

(c) (-32) + (-25)

(d) (+23) + (+40)

Solution:

(a) (-11) + (-12) = -[11 + 12] = -23

(b) (+10) + (+4) = + [10 + 4] + [14] = 14

(c) (- 32) + (- 25) = – [32 + 25] – [57] = -57

(d) (+23) + (40) = + [23 + 40] = + [63] = 63

Try These (Page 125).

Question 1.

Find the solution of the following:

(a) (- 7) + (+8)

(b) (-9) + (+13)

(c) (+7) + (-10)

(d) (+12) + (-7)

Solution:

(a) (-7) + (+8):

Opposite of (-7) is (+7) and (+8)

= (+7) + (+1)

(- 7) + (+ 8) = (- 7) + (+7) + (+1)

= 0 + (+1) [(-7) + (+7) = 0]

= + 1

(b) (-9) + (+13):

(+13) – (+9) + (+4)

(-9) + (+ 13) = (-9) + (+9) + (+4)

= 0 + (+4) [(-9) + (+9) = 0]

= + 4 = 4

(c) (+7) + (-10):

(-10) = (-7) + (-3)

(+7) + (-10) = (+7) + (-7) + (-3)

= 0 + (-3)

[(+7) + (-7) = 0]

= – 3

(e) (+12) + (-7):

(+12) = (Ā±7) + (+5)

(+12) + (-7) = (+7) + (+5) + (-7)

= (+7) + (-7) + (+5)

= – 0 + (+ 5)

= (+5)

= 5

[(+7) + (-7) = 0]

Try These (Page 127)

Question 1.

Find the solution of thĆ© following additions using a number line.

(a) (-2) + 6

(b) (-6) + 2

Make two such questions and solve them using the number line.

Solution:

(a) (-2) + 6

First move 2 steps to the left of 0 to reach at – 2. From here, move 6 steps to the right of – 2, to reach at 4.

(-2) + (+6) = + 4

(b) (-6) + 2:

On the number line, we first move 6 equal steps (each of 1 unit) to the left of 0, to reach at (-6). Now, move 2 steps to the right of (- 6) to reach at (- 4).

(-6) + (+2) = – 4

Question 2.

Find the solution of the following without using number line:

(a) (+7) + (-11)

(b) (-13) + (+10)

(c) (-7) + (+9)

(d) (+10) + (-5)

Make five such questions and solve them.

(a) (+7) + (-11):

(-11) = (-7) + (-4)

(+7) + (-11) = (+7) + (-7) + (-4) = 0 + (-4)

[(+7) + (-7) = 0] = – 4

Thus, (+7) + (-11) = – 4

(b) (-13) + (+10):

(-13) = (-10) + (-3)

(-13) + (+10) = (-10) + (-3) + (+10)

= (-10) + (+10) + (-3)

= 0 + (-3) = -3

[(-10) + (+ 10) = 0]

Thus, (- 13) + (+10) = – 3

(c) (-7) + (+9):

(+9) = (+7) + (+2)

(-7) + (+9) = (-7) + (+7) + (+2) = 0 + (+2)

[(- 7) + (+7) = 0]

= + 2

Thus, (- 7) + (+9) = + 2

(d) (+10) + (-5):

(+10) = (+5) + (+5)

(+10) + (-5) = (+5) + (+5) + (-5) = + 5 + 0

[(+5) + (-5) = 0]

Thus, (+10) + (-5) = (+5)