Gujarat BoardĀ GSEB Textbook Solutions Class 6 Maths Chapter 7 Fractions Ex 7.2 Textbook Questions and Answers.

## Gujarat Board Textbook Solutions Class 6 Maths Chapter 7 Fractions Ex 7.2

Question 1.

Draw number lines and locate the points on them:

Solution:

Here, we divide the length between 0 and 1 into 4 equal parts, then, we have:

\(\frac { 1 }{ 4 } \) is denoted by the point B.

\(\frac { 1 }{ 2 } \) is denoted by the point C.

\(\frac { 3 }{ 4 } \) is denoted by the point D.

\(\frac { 4 }{ 4 } \) is denoted by the point E.

From the figure, we have:

\(\frac { 1 }{ 8 } \) is denoted by the point B.

\(\frac { 2 }{ 8 } \) is denoted by the point C.

\(\frac { 3 }{ 8 } \) is denoted by the point D.

\(\frac { 7 }{ 8 } \) is denoted by the point H.

From the figure, we have:

\(\frac { 2 }{ 5 } \) is denoted by the point B.

\(\frac { 3 }{ 5 } \) is denoted by the point C.

\(\frac { 8 }{ 5 } \) is denoted by the point D.

\(\frac { 4 }{ 5 } \) is denoted by the point H.

Question 2.

Express the following as mixed fractions.

(a) \(\frac { 20 }{ 3 } \)

(b) \(\frac { 11 }{ 5 } \)

(c) \(\frac { 17 }{ 7 } \)

(d) \(\frac { 28 }{ 5 } \)

(e) \(\frac { 19 }{ 6 } \)

(f) \(\frac { 35 }{ 9 } \)

Solution:

(a) We have

\(\frac { 20 }{ 3 } \) = 6 \(\frac { 2 }{ 5 } \)

(b) We have

\(\frac { 11 }{ 5 } \) = 2 \(\frac { 1 }{ 5 } \)

(c) We have

\(\frac { 17 }{ 7 } \) = 2 \(\frac { 3 }{ 7 } \)

(d) We have

\(\frac { 28 }{ 5 } \) = 5 \(\frac { 3 }{ 5 } \)

(e) We have

\(\frac { 35 }{ 9 } \) = 3 \(\frac { 35 }{ 9 } \)

(f) We have

\(\frac { 35 }{ 9 } \) = 3 \(\frac { 8 }{ 9 } \)

Question 3.

Express the following as improper fractions:

(a) 7 \(\frac { 3 }{ 4 } \)

(b) 5 \(\frac { 6 }{ 7 } \)

(c) 2 \(\frac { 5 }{ 6 } \)

(d) 10 \(\frac { 3 }{ 5 } \)

(e) 9 \(\frac { 3 }{ 7 } \)

(f) 8 \(\frac { 4 }{ 9 } \)

Solution: