GSEB Solutions Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.4

Gujarat Board GSEB Textbook Solutions Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.4 Textbook Questions and Answers.

Gujarat Board Textbook Solutions Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.4

Question 1.
Find:
(i) 12 ÷ \(\frac { 3 }{ 4 }\)
(ii) 14÷ \(\frac { 5 }{ 6 }\)
(iii) 8 ÷ \(\frac { 7 }{ 3 }\)
(iv) 4 ÷ \(\frac { 8 }{ 3 }\)
(v) 3 ÷ 2\(\frac { 1 }{ 3 }\)
(vi) 5 ÷ 3\(\frac { 4 }{ 7 }\)
Solution:

Question 2.
Find the reciprocal of each of the following fractions. Classify the reciprocals as proper fractions, improper fractions and whole numbers.
(i) \(\frac { 3 }{ 7 }\)
(ii) \(\frac { 5 }{ 8 }\)
(iii) \(\frac { 9 }{ 7 }\)
(iv) \(\frac { 6 }{ 5 }\)
(v) \(\frac { 12 }{ 7 }\)
(vi) \(\frac { 1 }{ 8 }\)
(vii) \(\frac { 1 }{ 11 }\)
Solution:
(i) The recipocal of \(\frac { 3 }{ 7 }\) is \(\frac { 7 }{ 3 }\)
(improper fraction)

(ii) The reciprocal of \(\frac { 5 }{ 8 }\) is \(\frac { 8 }{ 5 }\);
(improper fraction)

(iii) The reciprocal of \(\frac { 9 }{ 7 }\) is \(\frac { 7 }{ 9 }\);
(proper fraction)

(iv) The reciprocal of \(\frac { 6 }{ 5 }\) is \(\frac { 5 }{ 6 }\)
(proper fraction)

(v) The reciprocal of \(\frac { 12 }{ 7 }\) is \(\frac { 7 }{ 12 }\)
(proper fraction)

(vi) The reciprocal of \(\frac { 1 }{ 8 }\) is 8;
(whole number)

(vii) The reciprocal of \(\frac { 1 }{ 11 }\) is 11;
(whole number)

Question 3.
Find:
(i) \(\frac { 7 }{ 3 }\) ÷ 2
(ii) \(\frac { 4 }{ 9 }\) ÷ 5
(iii) \(\frac { 6 }{ 13 }\) ÷ 7
(iv) 4\(\frac { 1 }{ 3 }\) ÷ 3
(v) 3\(\frac { 1 }{ 2 }\) ÷ 4
(vi) 4\(\frac { 4 }{ 7 }\) ÷ 7
Solution:
(i) \(\frac { 7 }{ 3 }\) ÷ 2
= \(\frac { 7 }{ 3 }\) x \(\frac { 1 }{ 2 }\)
= 1\(\frac { 1 }{ 6 }\)

(ii) \(\frac { 4 }{ 9 }\) ÷ 5
= \(\frac { 4 }{ 9 }\) x \(\frac { 1 }{ 5 }\)
= \(\frac { 4 }{ 45 }\)

(iii) \(\frac { 6 }{ 13 }\) ÷ 7
= \(\frac { 6 }{ 13 }\) x \(\frac { 1 }{ 7 }\)
= \(\frac { 6 }{ 91 }\)

(iv) 4\(\frac { 1 }{ 3 }\) ÷ 3
= \(\frac { 13 }{ 3 }\) x \(\frac { 1 }{ 3 }\)
= 1\(\frac { 4 }{ 9 }\)

(v) 3\(\frac { 1 }{ 2 }\) ÷ 4
= \(\frac { 7 }{ 2 }\) x \(\frac { 1 }{ 4 }\)
= \(\frac { 7 }{ 8 }\)

(vi) 4\(\frac { 4 }{ 7 }\) ÷ 7
= \(\frac { 31 }{ 7 }\) x \(\frac { 1 }{ 7 }\)
= \(\frac { 31 }{ 49 }\)

Question 4.
(i) \(\frac { 2 }{ 5 }\) ÷ \(\frac { 1 }{ 2 }\)
(ii) \(\frac { 4 }{ 9 }\) ÷ \(\frac { 2 }{ 3 }\)
(iii) \(\frac { 3 }{ 7 }\) ÷ \(\frac { 8 }{ 7 }\)
(iv) 2\(\frac { 1 }{ 3 }\) ÷ \(\frac { 3 }{ 5 }\)
(v) 3\(\frac { 1 }{ 2 }\) ÷ \(\frac { 8 }{ 3 }\)
(vi) 2\(\frac { 2 }{ 5 }\) ÷ 1\(\frac { 1 }{ 2 }\)
(vii) 3\(\frac { 1 }{ 5 }\) ÷ 1\(\frac { 2 }{ 3 }\)
(viii) 2\(\frac { 1 }{ 5 }\) ÷ 1\(\frac { 1 }{ 5 }\)
Solution: