Gujarat Board GSEB Textbook Solutions Class 7 Maths Chapter 10 Practical Geometry Ex 10.5 Textbook Questions and Answers.

## Gujarat Board Textbook Solutions Class 7 Maths Chapter 10 Practical Geometry Ex 10.5

Question 1.

Construct the right-angled ∆PQR, where m∠Q = 90°, QR = 8 cm and PR =10 cm.

Solution:

Steps of construction:

I. Draw a line segment QR = 8 cm.

II. At Q, construct ∠RQX = 90°.

III. With centre at R and radius 10 cm, draw an arc to cut \(\overrightarrow{\mathrm{QX}}\) at P.

IV. Join PR.

Thus, ∆PQR is the required right-angled triangle.

Question 2.

Construct a right-angled triangle whose hypotenuse is 6 cm long and one of the legs is 4 cm long.

Solution:

Steps of construction:

I. Draw a line segment MN = 4 cm.

II. Construct ∠NMX = 90° at M

III. With centre at N and radius 6 cm, draw an arc to cut \(\overrightarrow{\mathrm{MX}}\) at L.

IV. Join LN.

Thus, the ∆LMN is the required right-triangled triangle.

Question 3.

Construct an isosceles right-angled triangle ABC, where m∠ACB = 90° and AC = 6 cm.

Solution:

Steps of construction:

I. Draw a line segment AC = 6 cm.

II. At C, construct ∠ACX = 90°.

III. With centre C and radius AC = 6 cm, draw an arc to cut \(\overrightarrow{\mathrm{CX}}\) at B.

IV. Join BA.

Thus, ∆ABC is the required isosceles right-angled triangle.